9x^(2/3)-26x^(1/3)-3=0

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Solution for 9x^(2/3)-26x^(1/3)-3=0 equation: 


x in (-oo:+oo)

9*x^(2/3)-(26*x^(1/3))-3 = 0

9*x^(2/3)-26*x^(1/3)-3 = 0

t_1 = x^(1/3)

9*t_1^2-26*t_1^1-3 = 0

9*t_1^2-26*t_1-3 = 0

DELTA = (-26)^2-(-3*4*9)

DELTA = 784

DELTA > 0

t_1 = (784^(1/2)+26)/(2*9) or t_1 = (26-784^(1/2))/(2*9)

t_1 = 3 or t_1 = -1/9

t_1 = -1/9

x^(1/3)+1/9 = 0

1*x^(1/3) = -1/9 // : 1

x^(1/3) = -1/9

( -1/9 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 3

x^(1/3)-3 = 0

1*x^(1/3) = 3 // : 1

x^(1/3) = 3

x^(1/3) = 3 // ^ 3

x = 27

x = 27

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